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Group I and group II cations (Pb, Cu, Bi, Cd, As, Sb, Sn)

46 questions on Group I and group II cations (Pb, Cu, Bi, Cd, As, Sb, Sn) from the Qualitative Analysis: Cations chapter: 10 NEET level, 19 JEE Main, 17 JEE Advanced. Each one opens with its answer and solution.

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Dilute HCl is added to a cold solution of Pb(NO3)2. The precipitate formed is NEET level
When H2S is passed through a solution of CuSO4 acidified with dilute HCl, the precipitate formed is NEET level
A yellow precipitate is obtained when H2S is passed into a dilute-HCl solution of a salt. The cation present is NEET level
When a few drops of NH3 solution are added to Cu^2+ solution, a pale blue precipitate forms; with excess NH3 it dissolves to give a deep blue solution. The deep... NEET level
On pouring a clear solution of BiCl3 in dilute HCl into a large volume of water, a white turbidity appears. It is due to NEET level
Among the sulphides CuS, CdS, PbS and As2S3, the one that dissolves in yellow ammonium sulphide is NEET level
A yellow precipitate is formed when K2CrO4 is added to an acetic acid solution of a cation. The precipitate is insoluble in dilute acetic acid but dissolves in ... JEE Main level
Potassium hexacyanoferrate(II) is added to a solution of CuSO4 and a chocolate-brown precipitate Cu2[Fe(CN)6] forms. The oxidation state of iron in this precipi... JEE Main level
A solution contains Cu^2+ and Cd^2+. Excess KCN is added, and then H2S is passed. The result is JEE Main level
The equation 2Bi(OH)3 + 3[Sn(OH)4]^2- -> 2Bi + 3[Sn(OH)6]^2- describes the stannite test for bismuth. The moles of stannite required per mole of Bi(OH)3 is JEE Main level
SnCl2 solution is added dropwise to HgCl2 solution, and then in large excess. The sequence observed is JEE Main level
Brown SnS dissolves in yellow ammonium sulphide. The soluble product and the oxidation state of tin in it are JEE Main level
Match the sulphide in Column I with its colour in Column II. Column I: (P) PbS, (Q) CdS, (R) Sb2S3, (S) SnS. Column II: (1) yellow, (2) orange, (3) black, (4) b... JEE Main level
A white precipitate obtained on adding dilute H2SO4 to a lead salt solution dissolves in hot concentrated ammonium acetate. This is because JEE Main level
Black CuS is warmed with dilute HNO3 according to 3CuS + 8H+ + 2NO3- -> 3Cu^2+ + 3S + 2NO + 4H2O. The amount of NO liberated from 0.30 mol of CuS is JEE Main level
Which set contains only cations whose sulphides do NOT dissolve in yellow ammonium sulphide? JEE Main level
The yellow sulphide of arsenic is oxidised with concentrated HNO3 and the solution is warmed with ammonium molybdate in nitric acid. The observation and the oxi... JEE Main level
75.0 mL of 0.0860 M CuSO4 solution, acidified with dilute HCl, is treated with excess H2S. Assuming complete precipitation as CuS (molar mass 95.5 g mol^-1 from... JEE Main level
Select the correct statements about lead(II). JEE Advanced level
Select the correct statements about copper(II) in the qualitative scheme. JEE Advanced level
Select the correct statements about bismuth(III). JEE Advanced level
Tin(II) sulphide dissolves in yellow ammonium sulphide according to SnS + S2^2- -> SnS3^2-. Select the correct statements. JEE Advanced level
Which of the following sulphides dissolve in yellow ammonium sulphide? JEE Advanced level
A colourless salt solution turns turbid white on dilution with water. With H2S in dilute HCl it gives a dark brown precipitate that is insoluble in yellow ammon... JEE Advanced level
A yellow precipitate formed by H2S in dilute HCl is insoluble in yellow ammonium sulphide but dissolves in hot concentrated HCl. Its cation gives a colourless s... JEE Advanced level
A solution containing 0.714 g of Sn^2+ (Sn 119) as SnCl2 is treated with excess HgCl2 to give Hg2Cl2 (SnCl2 + 2HgCl2 -> SnCl4 + Hg2Cl2). All the Hg2Cl2 is then ... JEE Advanced level
Two equal samples, each containing 0.0200 mol of Pb^2+, are precipitated completely, one as PbSO4 with dilute H2SO4 and the other as PbCrO4 with K2CrO4 (Pb 207,... JEE Advanced level
In a Marsh-type test, 0.396 g of As2O3 (As 75, O 16) is reduced by zinc and acid: As2O3 + 6Zn + 12H+ -> 2AsH3 + 6Zn^2+ + 3H2O. Taking the molar volume at STP as... JEE Advanced level
Among the following cations, the one that is precipitated as its chloride by dilute HCl in the systematic analysis is NEET level
When H2S is passed through a solution of CuSO4 acidified with dilute HCl, the precipitate formed is NEET level
Passing H2S through a dilute-acid solution of Cd^2+ gives a precipitate of colour NEET level
The deep blue colour obtained when excess aqueous ammonia is added to a Cu^2+ salt solution is due to the ion NEET level
Assertion (A): Pb^2+ can be found in both group I and group II of the cation scheme. Reason (R): PbCl2 is appreciably soluble in cold water and dilute HCl, so p... JEE Main level
In the presence of 0.3 M HCl, H2S precipitates CuS but not ZnS. The correct reason is JEE Main level
A solution containing Cu^2+, Cd^2+, As^3+ and Bi^3+ sulphides (group II precipitate) is warmed with yellow ammonium sulphide. The sulphide that goes into soluti... JEE Main level
Bismuth(III) hydroxide is reduced to black metallic bismuth by sodium stannite: 2Bi(OH)3 + 3Na2SnO2 -> 2Bi + 3Na2SnO3 + 3H2O. The number of moles of stannite co... JEE Main level
Which of the following sulphides are insoluble in yellow ammonium sulphide (belong to group IIA)? JEE Main level
A solution of a salt gives a chocolate-brown precipitate with potassium hexacyanoferrate(II). The precipitate and the oxidation state of iron in it are JEE Main level
Match the test in Column I with the observation in Column II. Column I: (P) Cu^2+ + K4[Fe(CN)6]; (Q) Sn^2+ + excess HgCl2; (R) Cd^2+ + H2S (dil. acid); (S) Bi(O... JEE Main level
A mixture of Cu^2+ and Cd^2+ is treated with excess KCN. Copper(II) is reduced by cyanide: 2Cu^2+ + 10CN- -> 2[Cu(CN)4]^3- + (CN)2. When H2S is then passed, the... JEE Advanced level
A blue crystalline salt dissolves in water to give a blue solution. Dilute HCl gives no precipitate, H2S in acid gives a black precipitate soluble in hot dilute... JEE Advanced level
A solution is 0.010 M in each of Pb^2+, Cd^2+, Zn^2+ and Mn^2+ and is made 0.50 M in H+ and saturated with H2S ([H2S] = 0.10 M, K_1K_2 = 1.0x10^-21). Take K_sp:... JEE Advanced level
A solution is 0.30 M in HCl and is saturated with H2S ([H2S] = 0.10 M; overall K = [H+]^2[S^2-]/[H2S] = 1.0x10^-21). It contains cadmium(II) and K_sp(CdS) = 8.0... JEE Advanced level
Tin(II) chloride reduces mercury(II) chloride in two stages: 2HgCl2 + SnCl2 -> Hg2Cl2 + SnCl4 (white silky), then Hg2Cl2 + SnCl2 -> 2Hg + SnCl4 (grey). The tota... JEE Advanced level
Arsenic(III) sulphide (yellow) is oxidised completely by conc. HNO3 to arsenic acid H3AsO4 and sulphate. The number of electrons lost per formula unit of As2S3 ... JEE Advanced level
Regarding the tin sulphides in the analysis of group IIB, which statements are correct? JEE Advanced level