JEE Main levelSingle correct optionDifficulty 2 of 3qc176
Match the test in Column I with the observation in Column II.
Column I: (P) CuX2+ + KX4[Fe(CN)X6]; (Q) SnX2+ + excess HgClX2; (R) CdX2+ + HX2S (dil. acid); (S) Bi(OH)X3 + sodium stannite.
Column II: (1) yellow precipitate; (2) black precipitate; (3) chocolate-brown precipitate; (4) white silky precipitate.
AP-3, Q-4, R-1, S-2
BP-3, Q-2, R-1, S-4
CP-1, Q-4, R-3, S-2
DP-3, Q-4, R-2, S-1
Answer: A
Cu gives chocolate-brown CuX2[Fe(CN)X6] (3); Sn(II) reduces HgClX2 to white silky HgX2ClX2 (4); Cd gives yellow CdS (1); stannite reduces Bi(III) to black Bi (2). So P-3, Q-4, R-1, S-2.