Assertion (A): Pb^2+ can be found in both group I and group II of the cation scheme. Reason (R): PbCl2 is appreciably so

Question

Assertion (A): Pb^2+ can be found in both group I and group II of the cation scheme. Reason (R): PbCl2 is appreciably soluble in cold water and dilute HCl, so part of the lead stays in solution when group I is precipitated.

Accepted Answer

Both A and R are true and R is the correct explanation of A

Answer

A is false but R is true

Answer

A is true but R is false

Answer

Both A and R are true but R is not the correct explanation of A

Assertion (A): $Pb X^{2 +}$ can be found in both group I and group II of the cation scheme. Reason (R): $PbCl X_{2}$ is appreciably soluble in cold water and dilute HCl, so part of the lead stays in solution when group I is precipitated.

Answer: B

More questions on Group I and group II cations (Pb, Cu, Bi, Cd, As, Sb, Sn)

Assertion (A): PbX2+ can be found in both group I and group II of the cation scheme. Reason (R): PbClX2​ is appreciably soluble in cold water and dilute HCl, so part of the lead stays in solution when group I is precipitated.

Answer: B

More questions on Group I and group II cations (Pb, Cu, Bi, Cd, As, Sb, Sn)

Assertion (A): $Pb X^{2 +}$ can be found in both group I and group II of the cation scheme. Reason (R): $PbCl X_{2}$ is appreciably soluble in cold water and dilute HCl, so part of the lead stays in solution when group I is precipitated.