Tin(II) sulphide dissolves in yellow ammonium sulphide according to SnS + S2^2- -> SnS3^2-. Select the correct statements.

Acidifying the solution gives yellow SnS2 and H2S.

The disulphide ion S2^2- acts as the oxidising agent.

Acidifying the solution gives yellow SnS2 and H2S.

The disulphide ion S2^2- acts as the oxidising agent.

The same reaction would occur with colourless ammonium sulphide, which contains no polysulphide.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3qc049

Tin(II) sulphide dissolves in yellow ammonium sulphide according to $SnS + S X_{2} X^{2 -} SnS X_{3} X^{2 -}$ . Select the correct statements.

AAcidifying the solution gives yellow $SnS X_{2}$ and $H X_{2} S$ .
BThe disulphide ion $S X_{2} X^{2 -}$ acts as the oxidising agent.
CThe same reaction would occur with colourless ammonium sulphide, which contains no polysulphide.
DTin is oxidised from $+ 2$ to $+ 4$ .

Without extra sulphur, colourless

(NH X_{4}) X_{2} S

cannot oxidise

Sn X^{2 +}

Sn X^{4 +}

, so

SnS

does not dissolve in it. In yellow ammonium sulphide the polysulphide oxidises tin and is itself reduced; acidification follows

SnS X_{3} X^{2 -} + 2 H X^{+} SnS X_{2} + H X_{2} S