Regarding the tin sulphides in the analysis of group IIB, which statements are correct?

ASnS is brown and SnS $_{2}$ is yellow
B $SnS X_{2}$ dissolves in colourless ammonium sulphide as thiostannate
CSnS dissolves in colourless ammonium sulphide without oxidation
DYellow ammonium polysulphide oxidises SnS to a soluble thiostannate, $SnS X_{3} X^{2 -}$

Answer: A, B, D

SnS (Sn(II)) is brown and

SnS X_{2}

(Sn(IV)) yellow. Only the acidic Sn(IV) sulphide forms the thiostannate with

S X^{2 -}

; SnS is basic and does not dissolve in colourless

(NH X_{4}) X_{2} S

, but the polysulphide in the yellow reagent oxidises Sn(II) to Sn(IV) so SnS dissolves. Hence 1, 2 and 4.