MolSynapsequestion bank

MolSynapse / Question bank / Qualitative Analysis: Cations / Group I and group II cations (Pb, Cu, Bi, Cd, As, Sb, Sn)

JEE Main levelSingle correct optionDifficulty 2 of 3qc027

Brown $SnS$ dissolves in yellow ammonium sulphide. The soluble product and the oxidation state of tin in it are

A $SnS X_{2}$ (solid), $+ 4$
B $[SnS X_{3}] X^{2 -}$ , $+ 2$
C $[Sn (OH) X_{6}] X^{2 -}$ , $+ 4$
D $[SnS X_{3}] X^{2 -}$ , $+ 4$

Answer: D

The polysulphide oxidises

SnS

:

SnS + S X_{2} X^{2 -} SnS X_{3} X^{2 -}

, the thiostannate ion with tin in the

+ 4

state. A thio-anion is soluble, whereas

SnS X_{2}

is only obtained when the solution is acidified.

Practice Qualitative Analysis: Cations More on Group I and group II cations (Pb, Cu, Bi, Cd, As, Sb, Sn)

Previous questionNext question

More questions on Group I and group II cations (Pb, Cu, Bi, Cd, As, Sb, Sn)