Ozonolysis and oxidative cleavage

37 questions on Ozonolysis and oxidative cleavage from the Hydrocarbons chapter: 7 NEET level, 15 JEE Main, 15 JEE Advanced. Each one opens with its answer and solution.

• Ozonolysis of ethene followed by reductive work-up (Zn/H2O) gives NEET level
• Reductive ozonolysis of propene, CH3-CH=CH2, gives NEET level
• But-2-ene is heated with hot concentrated acidified KMnO4. The organic product is NEET level
• 2-Methylbut-2-ene is ozonised and the ozonide is worked up with H2O2 (oxidative work-up). The products are JEE Main level
• Cyclohexene is heated with hot concentrated acidified KMnO4. The product is JEE Main level
• 2-Methylpropene is treated with hot concentrated acidified KMnO4. The products are JEE Main level
• An alkene C5H10 on reductive ozonolysis gives only ethanal and propanal. The alkene is JEE Main level
• Reductive ozonolysis of which alkene gives propanone as the only organic product? JEE Main level
• Buta-1,3-diene, CH2=CH-CH=CH2, is subjected to ozonolysis with reductive work-up. The products are JEE Main level
• Which of the following does NOT give benzoic acid on oxidation with hot alkaline KMnO4 followed by acidification? JEE Main level
• Which of the following alkenes give ethanal as one of the products on reductive ozonolysis? JEE Main level
• 1-Methylcyclohexene is ozonised and then treated with H2O2 (oxidative work-up). The product is JEE Advanced level
• Cycloocta-1,5-diene is ozonised and worked up with Zn/H2O. The organic product(s) is/are JEE Advanced level
• A hydrocarbon A (C6H12) gives only propanone and propanal on reductive ozonolysis. A is then treated with HBr in the presence of peroxide. The major product is JEE Advanced level
• All acyclic structural isomers of C5H10 that contain one C=C bond (geometrical isomers counted once, i.e. constitutional isomers only) are ozonised and worked u... JEE Advanced level
• Which of the following alkenes give only carboxylic acid(s) (no ketone and no CO2) when treated with hot concentrated acidified KMnO4? JEE Advanced level
• Which of the following alkenes, on reductive ozonolysis, give at least one product that responds to the iodoform test? JEE Advanced level
• 2-Methylhepta-2,5-diene, (CH3)2C=CH-CH2-CH=CH-CH3, is subjected to ozonolysis with reductive work-up (Zn/H2O). Which statements are correct? JEE Advanced level
• Which of the following statements are correct? JEE Advanced level
• Ethene is treated with O3 and the ozonide is then decomposed with Zn / H2O. The product is NEET level
• Reductive ozonolysis of 2-methylpropene gives NEET level
• In the ozonolysis of alkenes, zinc dust is added in the work-up mainly to NEET level
• Ethene is shaken with cold, dilute, alkaline KMnO4 (Baeyer's reagent). The organic product is NEET level
• 2-Methylbut-2-ene is treated with O3 followed by H2O2 (oxidative work-up). The organic products are JEE Main level
• Which alkene gives propanone as the only organic product on reductive ozonolysis? JEE Main level
• Buta-1,3-diene is treated with excess O3 followed by Zn / H2O. The products are JEE Main level
• Cyclohexene is treated with O3 and then with dimethyl sulfide. The product is JEE Main level
• An equimolar mixture of pent-2-ene (both E and Z), 2-methylbut-2-ene, 3-methylpent-2-ene and hex-3-ene (both E and Z) is subjected to ozonolysis with reductive ... JEE Main level
• On reductive ozonolysis, which alkenes give propanone as one of the products? JEE Main level
• For propene, CH3-CH=CH2, which reagent(s) give ethanoic acid as an organic product? JEE Main level
• An alkene Y (C6H12) gives propanone and propanal on reductive ozonolysis. Y is hydrogenated completely and the alkane formed is monochlorinated by free radicals... JEE Advanced level
• 1-Methylcyclohexene is treated with O3 followed by H2O2. The organic product is JEE Advanced level
• A diene C5H8 on reductive ozonolysis gives 2 mol of methanal and 1 mol of propanedial, OHC-CH2-CHO, per mole of diene. The diene is JEE Advanced level
• An alkene X (C5H10) is oxidised by hot, acidified KMnO4 to a mixture of propanone and ethanoic acid. Addition of HBr (no peroxide) to X gives mainly JEE Advanced level
• Limonene is 1-methyl-4-(prop-1-en-2-yl)cyclohexene, C10H16, with one ring double bond and one isopropenyl double bond. It is treated with excess O3, followed by... JEE Advanced level
• 1,2-Dimethylcyclopentene is treated with O3, then Zn / H2O. Select the correct statement(s) about the organic product. JEE Advanced level
• Hexa-1,5-diene, CH2=CH-CH2CH2-CH=CH2, is subjected to ozonolysis. Select the correct statement(s). JEE Advanced level