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Ozonolysis and oxidative cleavage
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Difficulty 1 of 3
hc038
Reductive ozonolysis of propene,
CH
X
3
−
CH
=
CH
X
2
, gives
A
ethanal and methanal
B
propanal and methanal
C
propanone and methanal
D
two molecules of ethanal
Answer: A
The double bond is cleaved:
CH
X
3
−
CH
=
becomes
CH
X
3
CHO
and
=
CH
X
2
becomes
HCHO
.
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