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JEE Main levelOne or more correct optionsDifficulty 2 of 3hc139

For propene, $CH X_{3} - CH = CH X_{2}$ , which reagent(s) give ethanoic acid as an organic product?

A $O X_{3}$ followed by $H X_{2} O X_{2}$
Bhot, concentrated $KMnO X_{4}$ in acid
C $OsO X_{4}$ followed by $NaHSO X_{3}$
D $O X_{3}$ followed by $Zn$ / $H X_{2} O$

Answer: A, B

Strong oxidative cleavage (hot permanganate, or ozonolysis with oxidative work-up) oxidises the

CH X_{3} CH =

fragment to

CH X_{3} COOH

. Reductive ozonolysis stops at ethanal, and

OsO X_{4}

gives the diol without cleavage.

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