Answer: A
Limonene has two C=C bonds, so 2 mol of ozone are used. The ring bond opens to give a chain with CHX3COX− at one end and CHO at the other. The isopropenyl group becomes CHX3−C(=O)X− on the ring carbon and releases HCHO. The ring is opened, so the second product is one acyclic compound CHX3CO−CHX2CHX2−CH(COCHX3)−CHX2−CHO (CX9HX14OX3) plus methanal.