Answer: A
The ring double bond (CX1(CHX3)=CX2H) is cleaved. C1 (fully substituted) becomes a ketone CHX3−C(=O)X−; C2 bears H and becomes CHO, which the oxidative work-up converts into COOH. The chain is CHX3CO−(CHX2)X4−COOH, 6-oxoheptanoic acid. The aldehyde (6-oxoheptanal) would be obtained with Zn/H2O.