Benzene is treated with $\mathrm{CH}{}_3\mathrm{COCl}/\mathrm{AlCl}{}_3$ to give A. A is heated with $\mathrm{NaOH}/\mathrm{Br}{}_2$ (excess) and acidified to give B. B is treated with $\mathrm{SOCl}{}_2$ to give C, C with excess $\mathrm{NH}{}_3$ to give D, and D with $\mathrm{Br}{}_2/\mathrm{KOH}$ (heat) to give E. E is

A is acetophenone. The haloform reaction cleaves the $\mathrm{CH}{}_3\mathrm{CO}{}^{-}$ group to give benzoate, giving benzoic acid (B) after acidification and then benzoyl chloride (C). Ammonia gives benzamide (D). Hofmann bromamide degradation removes the carbonyl carbon, so E is $\mathrm{C}{}_6\mathrm{H}{}_5\mathrm{NH}{}_2$ (aniline).