An alkene C4H8 is treated with O3 followed by Zn/H2O and gives only one organic product, ethanal. The alkene is

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An alkene $C X_{4} H X_{8}$ is treated with $O X_{3}$ followed by $Zn / H X_{2} O$ and gives only one organic product, ethanal. The alkene is

Reductive ozonolysis cleaves

C = C

and puts

C = O

on each carbon.

CH X_{3} CH = CHCH X_{3}

is symmetrical and gives two molecules of

CH X_{3} CHO

. But-1-ene gives propanal and methanal, 2-methylpropene gives propanone and methanal, and methylcyclopropane has no

C = C