Answer: A, B, D
X is butan-2-one, CHX3COCHX2CHX3. NaBHX4 gives butan-2-ol, which has CHX3CH(OH)X− and gives iodoform. The haloform reaction gives CHX3CHX2COONa and CHIX3, so propanoic acid after acidification. Wolff-Kishner converts C=O to CHX2, giving butane. A ketone does not reduce Fehling solution.