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JEE Main levelSingle correct optionDifficulty 2 of 3si154

Propene is treated with $HBr$ in the presence of a peroxide to give A. A reacts with alcoholic $KCN$ to give B, and B is reduced with $LiAlH X_{4}$ to give C. C is

Apropan-1-amine
Bbutanamide
Cbutan-2-amine
Dbutan-1-amine

Answer: D

Peroxide effect gives anti-Markovnikov addition, so A is 1-bromopropane.

KCN

gives butanenitrile (B) with one extra carbon.

LiAlH X_{4}

reduces

- CN

to

- CH X_{2} NH X_{2}

, so C is

CH X_{3} CH X_{2} CH X_{2} CH X_{2} NH X_{2}

.

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