Aniline is treated with excess bromine water to give A. A is treated with NaNO2/HCl at 273 K to give B, and B is treated with hypophosphorous acid (H3PO2) to give C. C is

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Aniline is treated with excess bromine water to give A. A is treated with $NaNO X_{2} / HCl$ at $273 K$ to give B, and B is treated with hypophosphorous acid ( $H X_{3} PO X_{2}$ ) to give C. C is

Abromobenzene
B1,3,5-tribromobenzene
C2,4,6-tribromophenol
D1,2,4-tribromobenzene

Answer: B

Excess bromine water gives 2,4,6-tribromoaniline (A). Diazotisation gives the diazonium salt (B), and

H X_{3} PO X_{2}

replaces

- N X_{2} X^{+}

by H. The bromines stay at positions 2, 4 and 6 with respect to the former amino group, which are positions 1, 3 and 5 of C. C is 1,3,5-tribromobenzene.

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Aniline is treated with excess bromine water to give A. A is treated with NaNOX2​/HCl at 273 K to give B, and B is treated with hypophosphorous acid (HX3​POX2​) to give C. C is

Answer: B

More questions on Structure determination from reaction sequences

Aniline is treated with excess bromine water to give A. A is treated with $NaNO X_{2} / HCl$ at $273 K$ to give B, and B is treated with hypophosphorous acid ( $H X_{3} PO X_{2}$ ) to give C. C is