JEE Advanced levelNumerical answerDifficulty 3 of 3mc162
250 mL of 0.20 M NaCl is mixed with 350 mL of 0.15 M CaClX2 (volumes additive, complete dissociation). Find the concentration of chloride ions in mmol/L, to the nearest integer.
Numerical answer type, answer in mmol/L, tolerance 1.
Answer: 258 mmol/L
Cl- from NaCl = 250 x 0.20 = 50 mmol. Cl- from CaClX2 = 350 x 0.15 x 2 = 105 mmol. Total 155 mmol in 600 mL, i.e. 258.3 mmol/L, nearest integer 258.