The mole fraction of the solute in a 2.0 molal aqueous solution is ( $H X_{2} O = 18$ )

A $0.0347$
B $0.0020$
C $0.0360$
D $0.9653$

Answer: A

In 1 kg of water: solvent moles = 1000/18 = 55.56, solute = 2.0 mol. x = 2.0/(2.0 + 55.56) = 0.0347. The last distractor is the mole fraction of water.

Practice Mole Concept More on Concentration terms (molarity, molality, mole fraction, ppm) and dilution

Previous questionNext question

More questions on Concentration terms (molarity, molality, mole fraction, ppm) and dilution

To 100 mL of 0.6 M NaCl solution, water is added until the molarity becomes 0.25 M. Assuming volumes are additive, how many mL of water must... JEE Main level
An aqueous urea solution (M=60) is 2.0 molal and has density 1.03 g mL^-1. Find its molarity in mol L^-1, to two decimal places. JEE Main level
Which of the following concentration terms do not change with temperature for a given aqueous solution (ignore evaporation)? JEE Main level
A commercial nitric acid is 68% HNO3 by mass with density 1.41 g mL^-1 (M=63). The volume of this acid needed to prepare 500 mL of 0.50 M HN... JEE Advanced level
A 3.00 M aqueous solution of H2SO4 (M=98) has density 1.18 g mL^-1. Find its molality in mol kg^-1, to two decimal places. JEE Advanced level
250 mL of 0.20 M NaCl is mixed with 350 mL of 0.15 M CaCl2 (volumes additive, complete dissociation). Find the concentration of chloride ion... JEE Advanced level

The mole fraction of the solute in a 2.0 molal aqueous solution is (HX2​O=18)

Answer: A

More questions on Concentration terms (molarity, molality, mole fraction, ppm) and dilution

The mole fraction of the solute in a 2.0 molal aqueous solution is ( $H X_{2} O = 18$ )