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JEE Advanced levelSingle correct optionDifficulty 3 of 3mc160

A commercial nitric acid is 68% by mass with density (). The volume of this acid needed to prepare 500 mL of 0.50 M is

  1. A
  2. B
  3. C
  4. D

Answer: C

Molarity of the acid = 1.41 x 1000 x 0.68/63 = 15.22 M. Moles needed = 0.500 x 0.50 = 0.25 mol. Volume = 0.25/15.22 = 0.0164 L = 16.4 mL.
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More questions on Concentration terms (molarity, molality, mole fraction, ppm) and dilution