JEE Advanced levelOne or more correct optionsDifficulty 3 of 3mc165
100 mL of 0.50 M HX2SOX4 is mixed with 400 mL of 0.30 M NaOH (volumes additive, complete neutralisation of H+ by OH-). Which statements are correct?
AFinal [SOX4X2−]=0.20M
BThe final solution is basic
CFinal [OHX−]=0.040M
DFinal [NaX+]=0.24M
Answer: B, C, D
H+ = 100 x 0.50 x 2 = 100 mmol; OH- = 120 mmol, so OH- is in excess by 20 mmol and the solution is basic. [OH-] = 20/500 = 0.040 M. Na+ = 120/500 = 0.24 M. Sulphate = 50/500 = 0.10 M, so 0.20 is false.