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JEE Main levelNumerical answerDifficulty 2 of 3mc141

To 100 mL of 0.6 M NaCl solution, water is added until the molarity becomes 0.25 M. Assuming volumes are additive, how many mL of water must be added? Give the nearest integer.

Numerical answer type, answer in mL, tolerance 1.

Answer: 140 mL

Moles are constant: 0.6 x 100 = 0.25 x V, so V = 240 mL. Water added = 240 - 100 = 140 mL.
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More questions on Concentration terms (molarity, molality, mole fraction, ppm) and dilution