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JEE Main levelNumerical answerDifficulty 2 of 3mc140

A solution is made from 23 g of ethanol ( $C X_{2} H X_{5} OH$ , $M = 46$ ) and 90 g of water ( $M = 18$ ). Find the mole fraction of ethanol multiplied by 100, to two decimal places.

Numerical answer type, tolerance 0.02.

Answer: 9.09

Moles of ethanol = 23/46 = 0.5; moles of water = 90/18 = 5. x = 0.5/5.5 = 0.0909, so 100x = 9.09.

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