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Concentration terms (molarity, molality, mole fraction, ppm) and dilution
JEE Main level
Numerical answer
Difficulty 2 of 3
mc139
A water sample of mass 2.4 kg contains 5.5 mg of dissolved lead. Express the lead concentration in ppm by mass, to two decimal places.
Numerical answer type, answer in ppm, tolerance 0.01.
Answer: 2.29 ppm
ppm (mass) = (mass of solute/mass of solution) x
1
0
6
= (5.5e-3 g / 2400 g) x 1e6 = 2.29.
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