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JEE Main levelSingle correct optionDifficulty 2 of 3mc136

The molality of a solution prepared by dissolving 36 g of glucose () in 400 g of water is

  1. A
  2. B
  3. C
  4. D

Answer: B

Moles of glucose = 36/180 = 0.2. Mass of solvent = 0.400 kg. Molality = 0.2/0.400 = 0.50 mol/kg.
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More questions on Concentration terms (molarity, molality, mole fraction, ppm) and dilution