JEE Advanced levelSingle correct optionDifficulty 3 of 3mc087
One litre (taken as 1kg) of a hard water sample contains 55.5mg of CaClX2 (111g/mol) and 95mg of MgClX2 (95g/mol). Hardness is expressed as ppm of CaCOX3 (100g/mol) having the same total moles of cations. The hardness is
A150.5 ppm
B150 ppm
C75 ppm
D1.5 ppm
Answer: B
Moles of CaX2+ = 55.5/111 = 0.5 mmol; of MgX2+ = 95/95 = 1.0 mmol; total 1.5 mmol. Equivalent CaCOX3 = 1.5 mmol x 100 = 150 mg per kg = 150 ppm.