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JEE Advanced levelNumerical answerDifficulty 3 of 3mc089

An aqueous $NaOH$ solution ( $40 g/mol$ ) is $2.50 m$ (molal) and has density $1.15 g/mL$ . Find its molarity in mol/L, to two decimals.

Numerical answer type, answer in M, tolerance 0.01.

Answer: 2.61 M

Per 1 kg water there is 2.5 mol = 100 g

NaOH

, so solution mass = 1100 g. Volume = 1100/1.15 = 956.5 mL = 0.9565 L. Molarity = 2.5/0.9565 = 2.6136 M, i.e. 2.61 M.

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