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Concentration terms (molarity, molality, mole fraction, ppm) and dilution
JEE Advanced level
Single correct option
Difficulty 3 of 3
mc086
To prepare
500
mL
of
0.50
M
H
X
2
SO
X
4
(
98
g/mol
), what volume of concentrated acid (
98%
by mass, density
1.84
g/mL
) must be diluted?
A
25.0
mL
B
13.6
mL
C
13.3
mL
D
27.2
mL
Answer: B
Moles needed = 0.500 x 0.50 = 0.25 mol = 24.5 g of pure acid. Mass of 98% acid = 24.5/0.98 = 25 g. Volume = 25/1.84 = 13.6 mL.
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