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Concentration terms (molarity, molality, mole fraction, ppm) and dilution
JEE Advanced level
Single correct option
Difficulty 3 of 3
mc085
An aqueous urea (
CO
(
NH
X
2
)
X
2
,
60
g/mol
) solution is
3.0
M
and has density
1.05
g/mL
. Taking water as
18
g/mol
, the mole fraction of urea is
A
0.0621
B
0.0540
C
0.1714
D
0.0584
Answer: D
1 L weighs 1050 g and holds 3 x 60 = 180 g urea, so water = 870 g = 48.33 mol. Mole fraction = 3/(3 + 48.33) = 0.0584.
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