An aqueous $H X_{2} SO X_{4}$ solution ( $98 g/mol$ ) is $4.9%$ by mass and has density $1.03 g/mL$ . Choose the correct statement(s). (Water $18 g/mol$ .)

AThe molarity is $0.515 M$ .
BThe molality is equal to the molarity.
CThe molality is $0.526 m$ .
DThe mole fraction of $H X_{2} SO X_{4}$ is $0.0094$ .

Answer: A, C, D

Take 100 g of solution: 4.9 g acid = 0.05 mol, water 95.1 g = 5.283 mol, volume = 100/1.03 = 97.09 mL. Molarity = 0.05/0.09709 = 0.515 M (A true). Molality = 0.05/0.0951 = 0.526 m, which differs from molarity (B false, C true). Mole fraction = 0.05/(0.05+5.283) = 0.0094 (D true).

Practice Mole Concept More on Concentration terms (molarity, molality, mole fraction, ppm) and dilution

Previous questionNext question

An aqueous HX2​SOX4​ solution (98 g/mol) is 4.9% by mass and has density 1.03 g/mL. Choose the correct statement(s). (Water 18 g/mol.)

Answer: A, C, D

More questions on Concentration terms (molarity, molality, mole fraction, ppm) and dilution

An aqueous $H X_{2} SO X_{4}$ solution ( $98 g/mol$ ) is $4.9%$ by mass and has density $1.03 g/mL$ . Choose the correct statement(s). (Water $18 g/mol$ .)