$6.0 mL$ of $0.40 M$ $CuSO X_{4}$ solution is diluted with water to $2.0 L$ (take the density of the dilute solution as $1.00 g/mL$ ). Taking $Cu = 63.5$ , find the concentration of $Cu X^{2 +}$ in ppm by mass, to the nearest integer.

Numerical answer type, answer in ppm, tolerance 0.5.

Answer: 76 ppm

Moles of

Cu X^{2 +}

= 0.0060 x 0.40 = 0.0024 mol = 0.1524 g. Mass of solution = 2000 g. ppm = 0.1524/2000 x

1 0^{6}

= 76.2, i.e. 76 ppm.