Assuming square planar geometry for [PtCl4]^2-, which ion has the same hybridisation of the central metal as [PtCl4]^2-?

JEE Main levelSingle correct optionDifficulty 2 of 3cc183

Assuming square planar geometry for $[PtCl X_{4}] X^{2 -}$ , which ion has the same hybridisation of the central metal as $[PtCl X_{4}] X^{2 -}$ ?

Pt X^{2 +}

5 d^{8}

and gives a square planar

d s p^{2}

complex.

[Ni (CN) X_{4}] X^{2 -}

is also square planar

d s p^{2}

[NiCl X_{4}] X^{2 -}

[CoCl X_{4}] X^{2 -}

and

[Zn (NH X_{3}) X_{4}] X^{2 +}

are tetrahedral

s p^{3}