Answer: A, B
CrX3+ (d3) leaves two 3d orbitals empty, so it is inner orbital. FeX2+ (d6) with CNX− pairs up to t2g6, so it is inner orbital. [FeFX6]X3− is high spin (sp3d2) and NiX2+ (d8) cannot free two 3d orbitals, so [Ni(NHX3)X6]X2+ is sp3d2. Correct: options 1 and 2.