Which statement about the octahedral ion [Ni(NH3)6]^2+ is correct?

It is sp^3d^2 hybridised with two unpaired electrons (2.83 BM)

It is sp^3d^2 hybridised with a moment of 3.87 BM

It is sp^3d^2 hybridised with two unpaired electrons (2.83 BM)

It is d^2sp^3 hybridised and diamagnetic

It is d^2sp^3 hybridised with two unpaired electrons

JEE Main levelSingle correct optionDifficulty 2 of 3cc186

Which statement about the octahedral ion $[Ni (NH X_{3}) X_{6}] X^{2 +}$ is correct?

Ni X^{2 +}

3 d^{8}

(

t_{2 g}^{6} e_{g}^{2}

), so it has two unpaired electrons and cannot free two

3 d

orbitals for

d^{2} s p^{3}

. It therefore uses

4 s

4 p

and

4 d

orbitals (

s p^{3} d^{2}

, outer orbital).

μ = 8 = 2.83

BM.