Match the complex ion (List I) with its hybridisation and spin-only magnetic moment (List II). Assume [Ni(CN)4]^2- is square planar, [NiCl4]^2- is tetrahedral and F- is weak-field. List I: P [Ni(CN)4]^2-; Q [NiCl4]^2-; R [Fe(CN)6]^3-; S [FeF6]^3-. List II: 1 sp^3, 2.83 BM; 2 dsp^2, 0 BM; 3 d^2sp^3, 1.73 BM; 4 sp^3d^2, 5.92 BM.

JEE Main levelSingle correct optionDifficulty 2 of 3cc179

Match the complex ion (List I) with its hybridisation and spin-only magnetic moment (List II). Assume $[Ni (CN) X_{4}] X^{2 -}$ is square planar, $[NiCl X_{4}] X^{2 -}$ is tetrahedral and $F X^{-}$ is weak-field. List I: P $[Ni (CN) X_{4}] X^{2 -}$ ; Q $[NiCl X_{4}] X^{2 -}$ ; R $[Fe (CN) X_{6}] X^{3 -}$ ; S $[FeF X_{6}] X^{3 -}$ . List II: 1 $s p^{3}$ , $2.83$ BM; 2 $d s p^{2}$ , $0$ BM; 3 $d^{2} s p^{3}$ , $1.73$ BM; 4 $s p^{3} d^{2}$ , $5.92$ BM.

Ni X^{2 +}

d^{8}

, strong-field square planar,

d s p^{2}

, no unpaired electrons (2). Q: tetrahedral

d^{8}

s p^{3}

n = 2

2.83

BM (1). R:

Fe X^{3 +}

d^{5}

low spin,

d^{2} s p^{3}

n = 1

1.73

BM (3). S:

d^{5}

high spin,

s p^{3} d^{2}

n = 5

5.92

BM (4). So P-2, Q-1, R-3, S-4.