F- is a weak-field ligand, so the octahedral complex [MnF6]^3- is high spin. Calculate its spin-only magnetic moment in BM (answer to two decimals).

JEE Main levelNumerical answerDifficulty 2 of 3cc178

$F X^{-}$ is a weak-field ligand, so the octahedral complex $[MnF X_{6}] X^{3 -}$ is high spin. Calculate its spin-only magnetic moment in BM (answer to two decimals).

Numerical answer type, answer in BM, tolerance 0.01.

Mn(III) is

3 d^{4}

. In a high-spin octahedral field the configuration is

t_{2 g}^{3} e_{g}^{1}

, so

n = 4

unpaired electrons.

μ = n (n + 2) = 24 = 4.90

BM.