Answer: A, D
With ΔH∘=0 the slope −ΔH∘/R of lnK versus 1/T vanishes, so A is true. The correct equation has RT2 in the denominator, so B is false. For ΔH∘>0 and ΔS∘<0, ΔG∘=ΔH∘−TΔS∘ is positive at every temperature, so K<1 always and C is false. For D, ln(K2/K1)=(50000/8.314)(1/300−1/310)=0.6467, a factor of 1.91. The same 10 K rise near 600 K gives only 1.18.