JEE Main levelSingle correct optionDifficulty 2 of 3ce133
Take R=8.314Jmol−1K−1. A reaction has K=2.0×104 at 300K. The standard Gibbs energy change at 300K is
A+24.7kJmol−1
B−24.7kJmol−1
C−10.7kJmol−1
D−2.22kJmol−1
Answer: B
ΔG∘=−RTlnK=−(8.314)(300)ln(2.0×104)/1000=−(2494.2)(9.903)/1000=−24.7kJmol−1. Using log10 gives -10.7 and using T=27 instead of 300K gives -2.22, both wrong.