JEE Main levelSingle correct optionDifficulty 2 of 3ce085
Hydrogen reduces solid iron(II,III) oxide according to FeX3OX4(s)+4HX2(g)3Fe(s)+4HX2O(g), for which Kp=40 at the working temperature. At equilibrium the gas phase (only HX2 and HX2O) is at a total pressure of 2.0 atm. The partial pressure of HX2O in atm is
A1.00
B1.95
C0.57
D1.43
Answer: D
Kp=(pHX2O/pHX2)4=40, so pHX2O/pHX2=401/4=2.515. With pHX2O+pHX2=2.0: pHX2O=2.0×2.515/(1+2.515)=1.43 atm.