JEE Main levelSingle correct optionDifficulty 2 of 3ce083
At a certain temperature, C(s)+HX2O(g)CO(g)+HX2(g) has Kp1=1.6 atm and CO(g)+HX2O(g)COX2(g)+HX2(g) has Kp2=0.40. For C(s)+2HX2O(g)COX2(g)+2HX2(g) at the same temperature, Kp in atm is
A1.024
B0.64
C4.0
D2.0
Answer: B
Adding the two equations gives the required reaction (the CO cancels), so Kp=Kp1×Kp2=1.6×0.40=0.64 atm.