Excess CaCO3(s) is heated in an evacuated rigid 2.0 L vessel at 1100 K, where K_p = 0.50 atm for CaCO3(s) CaO(s) + CO2(g). Take R = 0.0821 L atm mol^-1 K^-1 and molar mass of CaCO3 = 100 g/mol. The mass of CaCO3 that decomposes is

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Excess $CaCO X_{3} (s)$ is heated in an evacuated rigid 2.0 L vessel at 1100 K, where $K_{p} = 0.50$ atm for $CaCO X_{3} (s) CaO (s) + CO X_{2} (g)$ . Take $R = 0.0821 L atm mo l^{- 1} K^{- 1}$ and molar mass of $CaCO X_{3}$ = 100 g/mol. The mass of $CaCO X_{3}$ that decomposes is

At equilibrium

p_{CO X_{2}} = K_{p} = 0.50

atm, so

n_{CO X_{2}} = p V / RT = 0.50 \times 2.0/ (0.0821 \times 1100) = 0.01107

mol. One mole of

CaCO X_{3}

gives one mole of

CO X_{2}

, so mass decomposed

= 0.01107 \times 100 = 1.11