Solid NH4Cl is in equilibrium with NH3(g) and HCl(g) in a rigid vessel at constant temperature, with p_NH3 = p_HCl = p_0. A little extra NH3(g) is now injected and equilibrium is re-established. Which statements are correct?

The new p_HCl is lower than p_0

The new total pressure is greater than 2p_0

The new p_HCl is lower than p_0

K_p increases because p_NH3 has increased

The new total pressure is greater than 2p_0

The mass of solid NH4Cl decreases

JEE Main levelOne or more correct optionsDifficulty 2 of 3ce086

Solid $NH X_{4} Cl$ is in equilibrium with $NH X_{3} (g)$ and $HCl (g)$ in a rigid vessel at constant temperature, with $p_{NH X_{3}} = p_{HCl} = p_{0}$ . A little extra $NH X_{3} (g)$ is now injected and equilibrium is re-established. Which statements are correct?

K_{p} = p_{NH X_{3}} p_{HCl} = p_{0}^{2}

is fixed at constant

T

. More

NH X_{3}

pushes the reaction backwards, so

HCl

is consumed (its pressure falls) and some solid

NH X_{4} Cl

forms (its mass increases). With the product fixed, unequal pressures have a sum larger than

2 p_{0}

(AM-GM). So statements 1 and 3 are correct.