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JEE Main levelSingle correct optionDifficulty 2 of 3ce084

For $C (s) + CO X_{2} (g) 2 CO (g)$ , $K_{p} = 1.9$ atm at 1000 K. Using $R = 0.0821 L atm mo l^{- 1} K^{- 1}$ , $K_{c}$ in $mol L^{- 1}$ is

A $1.9$
B $2.31 \times 1 0^{- 2}$
C $2.82 \times 1 0^{- 4}$
D $156$

Answer: B

Only gases count in

Δ n

:

Δ n = 2 - 1 = + 1

(carbon is a solid).

K_{c} = K_{p} / RT = 1.9/ (0.0821 \times 1000) = 2.31 \times 1 0^{- 2} mol L^{- 1}

.

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