Beryllium carbide and aluminium carbide both react with water to give the same hydrocarbon gas G and the corresponding amphoteric hydroxide. If 0.10 mol of $Be X_{2} C$ and 0.10 mol of $Al X_{4} C X_{3}$ are hydrolysed separately and the gases are pooled, the volume of G at STP (22.4 L per mol) is

Answer: D

Be X_{2} C + 4 H X_{2} O 2 Be (OH) X_{2} + CH X_{4}

gives 1 mol G per mol, and

Al X_{4} C X_{3} + 12 H X_{2} O 4 Al (OH) X_{3} + 3 CH X_{4}

gives 3 mol G per mol. Total G

= 0.10 + 0.30 = 0.40

mol, so volume

= 0.40 \times 22.4 = 8.96