Equal numbers of moles of anhydrous $LiNO X_{3}$ and $NaNO X_{3}$ are heated strongly until decomposition is complete, giving the oxide and nitrogen dioxide with oxygen for lithium, but the nitrite and oxygen for sodium. The ratio (moles of gas from LiNO3) : (moles of gas from NaNO3) is

Answer: B

Per mole,

4 LiNO X_{3} 2 Li X_{2} O + 4 NO X_{2} + O X_{2}

gives

1 + 0.25 = 1.25

mol gas, and

2 NaNO X_{3} 2 NaNO X_{2} + O X_{2}

gives 0.5 mol gas. The ratio is

1.25/0.50 = 2.5