Consider the amount of acidified KMnO4 (to Mn^2+) consumed by 0.1 mol of each of FeSO4, H2C2O4, FeC2O4 and H2O2 (oxidised to Fe^3+, CO2, Fe^3+ + CO2 and O2 respectively). Select the correct statement(s).

FeC2O4 consumes three times as much KMnO4 as FeSO4

H2C2O4 and H2O2 consume equal amounts

A mixture of all four (0.1 mol each) consumes 0.16 mol of KMnO4

FeC2O4 consumes three times as much KMnO4 as FeSO4

H2C2O4 and H2O2 consume equal amounts

FeSO4 and H2C2O4 consume equal amounts

A mixture of all four (0.1 mol each) consumes 0.16 mol of KMnO4

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3rx163

Consider the amount of acidified $KMnO X_{4}$ (to $Mn X^{2 +}$ ) consumed by $0.1$ mol of each of $FeSO X_{4}$ , $H X_{2} C X_{2} O X_{4}$ , $FeC X_{2} O X_{4}$ and $H X_{2} O X_{2}$ (oxidised to $Fe X^{3 +}$ , $CO X_{2}$ , $Fe X^{3 +}$ + $CO X_{2}$ and $O X_{2}$ respectively). Select the correct statement(s).

Equivalents (0.1 mol each):

FeSO X_{4}

0.1,

H X_{2} C X_{2} O X_{4}

0.2,

FeC X_{2} O X_{4}

0.3,

H X_{2} O X_{2}

0.2. So A and B are true and C is false. Total

= 0.8

eq, so

KMnO X_{4} = 0.8/5 = 0.16

mol (D true).