JEE Advanced levelOne or more correct optionsDifficulty 3 of 3rx164
Acidified 0.1 mol FeX2+ is oxidised to FeX3+. Select the oxidant amount(s) that react exactly completely with it (MnOX4X−MnX2+, CrX2OX7X2−CrX3+, HX2OX2HX2O).
A0.02 mol KMnOX4
B0.0167 mol KX2CrX2OX7
C0.10 mol HX2OX2
D0.02 mol KX2CrX2OX7
Answer: A, B
Equivalents of FeX2+=0.1. KMnOX4 (n=5): 0.1/5=0.02 mol (A true). KX2CrX2OX7 (n=6): 0.1/6=0.0167 mol (B true; D false). HX2OX2 (n=2): 0.05 mol, so C (0.10 mol) is false.