Use Br = 80. Bromine disproportionates in hot alkali: 3Br2 + 6NaOH -> 5NaBr + NaBrO3 + 3H2O. For 0.3 mol of Br2 reacting completely, select the correct statement(s).

0.5 mol of electrons are transferred

The equivalent mass of Br2 is 160

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3rx162

Use Br = 80. Bromine disproportionates in hot alkali: $3 Br X_{2} + 6 NaOH 5 NaBr + NaBrO X_{3} + 3 H X_{2} O$ . For $0.3$ mol of $Br X_{2}$ reacting completely, select the correct statement(s).

Per 3

Br X_{2}

: 5

NaBr

, 1

NaBrO X_{3}

, 5 electrons. For 0.3 mol:

NaBr = 0.5

mol, electrons

= 0.5

mol, so A and B are true.

n = 5/3

(C true). Equivalent mass

= 160/ (5/3) = 96

, not 160 (D false).