Molar volume at STP is 22.4 L/mol. A mixture of 0.1 mol FeC2O4 and 0.05 mol Fe2(C2O4)3 is titrated with acidified KMnO4 (to Mn^2+). Fe^3+ is not changed; Fe^2+ -> Fe^3+; oxalate -> CO2. Select the correct statement(s).

11.2 L of CO2 is evolved at STP

Fe2(C2O4)3 contributes 0.3 equivalents

11.2 L of CO2 is evolved at STP

250 mL of 0.4 M KMnO4 is consumed

Fe2(C2O4)3 contributes 0.3 equivalents

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3rx160

Molar volume at STP is $22.4 L/mol$ . A mixture of $0.1$ mol $FeC X_{2} O X_{4}$ and $0.05$ mol $Fe X_{2} (C X_{2} O X_{4}) X_{3}$ is titrated with acidified $KMnO X_{4}$ (to $Mn X^{2 +}$ ). $Fe X^{3 +}$ is not changed; $Fe X^{2 +} Fe X^{3 +}$ ; oxalate $CO X_{2}$ . Select the correct statement(s).

Equivalents:

FeC X_{2} O X_{4}

0.1 \times 3 = 0.3

;

Fe X_{2} (C X_{2} O X_{4}) X_{3}

0.05 \times 6 = 0.3

(six oxalate, Fe

^{3 +}

inert); total

0.6

KMnO X_{4} = 0.6/5 = 0.12

mol (A true).

CO X_{2} = 0.2 + 0.3 = 0.5

mol

= 11.2 L

(B true). Volume of

0.4 M

0.12/0.4 = 300 mL

, not the stated value (C false). D is true.