In acidic medium, KMnO4 oxidises oxalic acid to CO2 (n-factor of KMnO4 = 5, of H2C2O4 = 2). The number of moles of KMnO4 required per mole of H2C2O4 is:

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In acidic medium, $KMnO X_{4}$ oxidises oxalic acid to $CO X_{2}$ ( $n$ -factor of $KMnO X_{4}$ = 5, of $H X_{2} C X_{2} O X_{4}$ = 2). The number of moles of $KMnO X_{4}$ required per mole of $H X_{2} C X_{2} O X_{4}$ is:

Equivalents must match:

x \times 5 = 1 \times 2

, so

x = 2/5 = 0.4

mol.