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Stoichiometry of redox reactions
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rx111
Use K = 39, Mn = 55, O = 16. In acidic medium
MnO
X
4
X
−
is reduced to
Mn
X
2
+
. The equivalent mass of
KMnO
X
4
in this medium is:
A
31.6
B
52.7
C
158
D
79.0
Answer: A
Mn changes from +7 to +2, so
n
-factor = 5. Equivalent mass =
M
/
n
=
158/5
=
31.6
.
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